Free MOEMS Olympiad practice test — Grade 6
10 original MOEMS Olympiad-style questions for Grade 6, with answers and full explanations. No signup needed.
Practice in the spirit of MOEMS — five-problem elementary and middle-school math olympiads that stretch problem-solving beyond the classroom.
Each problem rewards a strategy: draw it, simplify it, find the pattern, work backwards.
- A14
- B15
- C16
- D17
Show answer & explanation
Correct answer: D
The pattern of the sequence is obtained by adding 1, 2, 3, 4,... to the previous term. Therefore, to get the next number, we add 5 to the last term, which is 11. So, 11 + 5 = 16. 💡 Tip: Look for patterns in the differences between consecutive terms.
- A80
- B120
- C160
- D200
Show answer & explanation
Correct answer: B
To maximize the number of members, we need to minimize the overlap between clubs. Since each member can join at most 3 clubs, we can divide the 15 clubs into 5 groups of 3 clubs each. Each group can have 8 members, and since each member joins 3 clubs, each group contributes 8 new members. Therefore, the maximum number of members is 5 groups * 8 members/group * 3 clubs/group / 3 clubs/member = 160 / 3 * 3 = 160. 💡 Tip: Divide the clubs into groups to minimize overlap and maximize the number of members.
- A92
- B100
- C108
- D116
Show answer & explanation
Correct answer: C
To find the area of the path, first calculate the area of the larger rectangle including the path, which is (15+2+2) * (8+2+2) = 19 * 12 = 228. Then subtract the area of the garden, 15 * 8 = 120. The area of the path is 228 - 120 = 108. 💡 Tip: When calculating the area of the path around a shape, it's helpful to visualize the larger shape that includes the original figure and the path, and then subtract the area of the original figure.
- A120
- B100
- C105
- D102
Show answer & explanation
Correct answer: A
To solve this, first find the least common multiple (LCM) of 3, 4, and 5, which is 60. Then, find the smallest 3-digit multiple of 60, which is 120. Since 120 has only two different prime factors (2 and 3), it satisfies all conditions. 💡 Tip: Remember, the LCM of numbers gives the smallest number that is a multiple of each of the given numbers. Also, prime factorization helps in identifying the number of different prime factors.
- A16
- B24
- C32
- D40
Show answer & explanation
Correct answer: B
To find the minimum number of additional books needed, we need to find the least common multiple (LCM) of 3 and 8. Since 3 x 8 = 24, we can add 24 books to make each shelf have 48 books (16 per row x 3 rows). Currently, there are 120 books, so each shelf has 120 / 3 = 40 books. To make each shelf have 48 books, we need 48 - 40 = 8 books per shelf. Since there are 3 shelves, we need 8 x 3 = 24 books. 💡 Tip: Pay attention to the shelf capacity and the current number of books.
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Start free diagnostic- A40 books
- B160 books
- C200 books
- D400 books
Show answer & explanation
Correct answer: B
Since each book has a thickness of 1 cm and the bookshelf has a height of 250 cm, we can fit 250 books on the bookshelf if we fill it completely. However, the bookshelf has 5 shelves, each of which can hold 8 books. So, the total number of books the bookshelf can hold is 5 * 8 = 40, if we consider the shelves. But the actual limiting factor is the height, and since 250 cm can fit 250 books, and we know that 5 * 8 = 40, we can fit 40 * 4 = 160 books (as 5 shelves would take 5 cm for the shelves themselves, leaving 250 - 5 = 245 cm, which is roughly 4 times the height of 8 books, which is 8 cm). Thus, the answer is 160 books. 💡 Tip: Consider all the given constraints and how they relate to each other.
- AFlip the switches in a specific sequence and then enter the room
- BEnter the room, turn on all the switches, and then turn them off one by one
- CTurn on each switch for 5 minutes and then turn it off
- DFlip the switches in any sequence and then enter the room
Show answer & explanation
Correct answer: A
To solve this problem, you can flip the switches in a specific sequence, for example: turn switch 1 to ON for 5 minutes, then turn it OFF. Turn switch 2 to ON for 5 minutes, then turn it OFF. Turn switch 3 to ON and leave it ON. Turn switch 4 to ON for 2.5 minutes and then turn it OFF. Turn switch 5 to ON and leave it ON. Then, enter the room and observe the bulbs. The hot bulb (but off) corresponds to switch 2, the bulb that is on corresponds to either switch 3 or switch 5, and the cold bulb (but off) that is not corresponding to switch 2 corresponds to either switch 1 or switch 4. By the process of elimination, you can figure out which switch corresponds to which bulb. 💡 Tip: Use a specific sequence of switch flips to create a unique pattern for each bulb.
- A5
- B10
- C10√3
- D20
Show answer & explanation
Correct answer: B
In a 30-60-90 triangle, the side opposite the 30-degree angle is half the length of the hypotenuse. Since the side opposite the 30-degree angle is 5 inches, the hypotenuse must be twice that, which is 10 inches. 💡 Tip: Knowing the properties of special triangles like 30-60-90 and 45-45-90 can be very helpful in geometry problems.
- A1008
- B1024
- C1000
- D1004
Show answer & explanation
Correct answer: A
First, find the least common multiple of 4 and 9, which is 36. Then, find the smallest 4-digit multiple of 36, which is 1008. Thus, 1008 is the smallest 4-digit number that is doubly divisible by 4 and 9. 💡 Tip: Finding the LCM of the divisors and then the smallest multiple of that LCM which fits the given constraints is key.
- A5
- B6
- C7
- D8
Show answer & explanation
Correct answer: B
First, subtract the 2 friends who don't want any candy from the total number of friends: 8 - 2 = 6. Then, divide the total number of pieces of candy by the number of friends who want candy: 48 / 6 = 8. 💡 Tip: Identify the number of friends who want candy before dividing the total number of pieces.
MOEMS Olympiad FAQ
What is MOEMS?
Math Olympiads for Elementary and Middle Schools — five monthly contests per school year, run through school teams, for grades 4–8.
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