Free Math Kangaroo practice test — Grade 5
10 original Math Kangaroo-style questions for Grade 5, with answers and full explanations. No signup needed.
Practice in the style of Math Kangaroo — playful, puzzle-like problems that reward insight over speed.
Contest math builds exactly the flexible thinking gifted programs look for, even if your child never competes.
- A$0.05
- B$0.10
- C$0.15
- D$0.20
Show answer & explanation
Correct answer: A
Let's denote the cost of the ball as x. The bat costs $1.00 more than the ball, so the bat costs x + $1.00. The total cost of the bat and the ball together is $1.10, so we can write the equation: x + (x + $1.00) = $1.10. Simplifying the equation, we get 2x + $1.00 = $1.10. Subtracting $1.00 from both sides, we get 2x = $0.10. Dividing both sides by 2, we get x = $0.05. 💡 Tip: Use algebra to represent the unknown cost of the ball and set up an equation based on the given information.
- A14
- B15
- C16
- D17
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Correct answer: B
Looking at the differences between consecutive terms: +1 (from 1 to 2), +2 (from 2 to 4), +3 (from 4 to 7), +4 (from 7 to 11). The pattern in the differences is adding 1 more each time. So, the next difference should be +5, making the next number in the sequence 11 + 5 = 16. 💡 Tip: Identify the pattern in the differences between terms to predict the next number in the sequence.
- A1
- B2
- C3
- D4
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Correct answer: B
First, let's calculate the total number of books added to the bookshelf: 20 + 15 = 35 books. Then, 8 books are removed, resulting in 35 - 8 = 27 books. Since each shelf can hold 8 books, we divide the total number of books by the capacity of each shelf: 27 ÷ 8 = 3 with a remainder of 3. This means that 3 shelves will be completely filled with 8 books each, and there will be 3 books left over for the next shelf. 💡 Tip: Pay attention to the order of operations and the remainder when dividing the total number of books by the capacity of each shelf.
- A1/9
- B4/9
- C8/9
- D5/9
Show answer & explanation
Correct answer: C
Let's denote the side length of the large square as S. The area of the large square is S^2. The side length of the small square is 1/3 * S, so its area is (1/3 * S)^2 = 1/9 * S^2. The area left after the cut is S^2 - 1/9 * S^2 = 8/9 * S^2. Thus, the fraction of the original area left is 8/9. 💡 Tip: Visualize the problem, understand the relationship between the areas of the squares, and calculate the fraction of the area left after the cut.
- A18 days
- B20 days
- C22 days
- D28 days
Show answer & explanation
Correct answer: B
The snail climbs 3 feet up and slips 2 feet back each day, so it effectively moves 1 foot up each day. However, on the last day of its climb to the top, it won't slip back. Thus, we need to find out how many days it takes to climb 17 feet (20 - 3 = 17), because on the 18th day, when it climbs the final 3 feet, it will reach the top and won't slip back. Since the snail moves 1 foot up effectively each day, it takes 17 days to climb 17 feet. On the 18th day, it climbs the last 3 feet to reach the top. 💡 Tip: Consider the net progress of the snail each day and the final day's climb to the top.
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Start free diagnostic- A32
- B48
- C64
- D96
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Correct answer: D
Let's denote the number of boys as 3x and the number of girls as 5x. Since there are 24 more girls than boys, 5x - 3x = 24. This simplifies to 2x = 24, meaning x = 12. So, the number of boys is 3*12 = 36, and the number of girls is 5*12 = 60. The total number of students is 36 + 60 = 96. 💡 Tip: Use algebra to represent the ratio and solve for the total number of students.
- A18
- B19
- C20
- D21
Show answer & explanation
Correct answer: B
The snail climbs 3 feet during the day and slips 2 feet back at night, making a net progress of 1 foot per day. To reach the top of the 20-foot well, it needs to make 18 days of net progress (18 feet) and then climb the final 2 feet on the 19th day to reach the top. 💡 Tip: Consider the net progress of the snail each day, taking into account both its upward movement and downward slip.
- A4 cm
- B6 cm
- C8 cm
- D12 cm
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Correct answer: C
Using the Pythagorean theorem, we have c^2 = a^2 + b^2, where c = 10 cm and a = 6 cm. Thus, 10^2 = 6^2 + b^2, which gives us 100 = 36 + b^2. Then, b^2 = 100 - 36 = 64, so b = sqrt(64) = 8 cm. 💡 Tip: Apply the Pythagorean theorem to find the length of the other leg of the right triangle.
- A6 boxes of each type
- B8 boxes of the first type and 4 boxes of the second type
- C4 boxes of the first type and 8 boxes of the second type
- D10 boxes of the first type and 2 boxes of the second type
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Correct answer: B
Let x be the number of boxes with 3 red and 6 blue crayons, and y be the number of boxes with 4 red and 5 blue crayons. We know Tom has 12 boxes in total, so x + y = 12. We also know he has a total of 60 blue crayons. Since each box of the first type has 6 blue crayons and each box of the second type has 5 blue crayons, we can write the equation 6x + 5y = 60. Now, we have two equations to solve for x and y. 💡 Tip: Represent the unknown number of boxes of each type with variables and set up equations based on the total number of boxes and the total number of blue crayons.
- A4
- B6
- C8
- D16
Show answer & explanation
Correct answer: C
To have exactly 5 factors, a number must be a fourth power of a prime number, because its factors would then be 1, the prime number, the square of the prime number, the cube of the prime number, and the fourth power of the prime number. The smallest fourth power of a prime number is 2^4 = 16. 💡 Tip: Understand the properties of factors and prime numbers to determine the smallest number with exactly 5 factors.
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Once a year, on the third Thursday of March, for grades 1–12 — registration typically opens the preceding fall.
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