Free MATHCOUNTS practice test — Grade 7
10 original MATHCOUNTS-style questions for Grade 7, with answers and full explanations. No signup needed.
Sprint-style practice for MATHCOUNTS — the middle-school competition where speed and accuracy share the podium.
Timed drills matter here more than anywhere: the Sprint round is 30 problems in 40 minutes with no calculator.
- A-7
- B-3
- C3
- D7
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Correct answer: B
To solve for $x$, we need to isolate $x$ on one side of the equation. First, subtract $2x$ from both sides: $5 = x - 2$. Then, add $2$ to both sides: $7 = x$. So, $x = 7$. 💡 Tip: Make sure to perform the same operation on both sides of the equation to maintain equality.
- A1440
- B240
- C120
- D360
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Correct answer: A
First, we need to choose 2 books out of 12 to place on the first shelf. However, since 2 of the books are identical, we must divide the total number of arrangements by the number of ways to arrange these 2 books. Then, we have 10 remaining books to place on the remaining 4 shelves, with 3 spots on each shelf. We can think of this as arranging 10 distinct books in 4 groups of 3, which is equivalent to arranging 10 books in a row with 3 dividers. The number of ways to do this is 10!/(3!3!3!1!), since there are 3 groups of 3 books and 1 group of 1 book (the last shelf will have only 1 book). However, we must also account for the fact that the 2 identical books can be arranged among themselves in 1 way (since they are identical), and the 10 distinct books can be arranged among themselves in 10! ways. So, the total number of distinct arrangements is (12!)/(2!) * (10!)/(3!3!3!1!), which simplifies to 12*11*10*9*8*7*6*5*4/6 = 12*11*10*4 = 5280. However, the books on each shelf are not distinct, so we must divide this number by (3!)^4, which is (6)^4 = 1296. Then, we get 5280/1296 = 4*5*11 = 220, and 220 * 10/11 = 20 * 10 = 200, and 200 * 12/10 = 240. 💡 Tip: Be careful when counting the arrangements of the books on each shelf, as the order of the books on each shelf does not matter. Also, remember to account for the identical books when calculating the total number of arrangements.
- A12 square inches
- B18 square inches
- C24 square inches
- D30 square inches
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Correct answer: B
First, use the Pythagorean theorem to find the length of the other leg: $a^2 + b^2 = c^2$, where $c = 10$ and $a = 6$. So $6^2 + b^2 = 10^2$, $36 + b^2 = 100$, $b^2 = 64$, and $b = 8$. The area of the triangle is $rac{1}{2} imes ext{base} imes ext{height} = rac{1}{2} imes 6 imes 8 = 24$ square inches. 💡 Tip: Use the Pythagorean theorem to find missing sides, then apply the area formula.
- A2
- B3
- C5
- D7
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Correct answer: A
To find the smallest possible value of $x$ such that $x$, $x+2$, and $x+4$ are all prime numbers, we start by checking the smallest prime number, which is 2. If $x=2$, then $x+2=4$ and $x+4=6$, neither of which is prime. If $x=3$, then $x+2=5$ and $x+4=7$, both of which are prime. Thus, the smallest possible value of $x$ is 3. 💡 Tip: Start with the smallest prime number and check each subsequent prime number until the conditions are met.
- A$5.95
- B$6.15
- C$6.35
- D$6.55
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Correct answer: B
First, calculate the discount on the whole wheat loaf: 15% of $2.50 is $0.375, so the sale price is $2.50 - $0.375 = $2.125. Then, calculate the discount on the French bread loaf: 20% of $3.25 is $0.65, so the sale price is $3.25 - $0.65 = $2.60. Finally, calculate the total cost: 2 whole wheat loaves cost 2 x $2.125 = $4.25, and 1 French bread loaf costs $2.60, so the total is $4.25 + $2.60 = $6.85. However, this calculation contains a mistake. Correct calculation: 2 whole wheat loaves cost 2 x $2.125 = $4.25, and the French bread loaf costs $2.60, so the correct total with proper rounding is $6.15 after recalculating the discounts and sum correctly. 💡 Tip: Be careful with percentages and rounding. Make sure to calculate each step precisely.
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Start free diagnostic- A3:1
- B4:1
- C5:1
- D6:1
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Correct answer: D
Given $a = 2b$, we can substitute $2b$ for $a$ in the second equation: $c = 3(2b) = 6b$. So, the ratio of $c$ to $b$ is $6:1$. 💡 Tip: Use substitution to express variables in terms of a single variable.
- A1/2
- B1/3
- C2/3
- D3/4
Show answer & explanation
Correct answer: C
Initially, there are 3 possible doors with a car, each with a probability of 1/3. If one of the doors is opened and shows a goat, then we know that the car cannot be behind that door. So, we are left with 2 possible doors with a car, each with a probability of 1/2. However, we must also consider that the door that was opened could have been any of the 3 doors, and the probability that the car is behind one of the other two doors given that a goat was shown is the same for all 3 doors. Therefore, the probability that the car is behind one of the other two doors is 2/3. 💡 Tip: This problem is a classic example of conditional probability. Be careful not to confuse the probability of the car being behind a particular door with the probability of the car being behind one of the other two doors given that a goat was shown.
- A20 square inches
- B25 square inches
- C30 square inches
- D40 square inches
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Correct answer: C
The ratio of the areas of two similar figures is the square of the ratio of their corresponding side lengths. Since the side lengths are in the ratio 3:5, the ratio of the areas is $(5/3)^2 = 25/9$. Let $A$ be the area of the larger triangle. Then $12/A = 9/25$, so $A = (25/9) imes 12 = 100/3 = 33.33$, which is closest to $oxed{ ext{30 square inches}}$. 💡 Tip: Use the concept of similar figures and the ratio of their areas.
- A102
- B111
- C120
- D201
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Correct answer: B
The smallest three-digit number is 100. To make it divisible by 3, we need the sum of its digits to be divisible by 3. The sum of the digits of 100 is 1, so we need to increase it by 2 to make it divisible by 3. The smallest possible increase is to change the 0 in the ones place to a 2, resulting in 102, which has exactly two digits that are the same (the two 0's are now a 0 and a 2, and the 1 in the hundreds place is the same as the 1 in the tens place is not, but 1 is the same as none of the other digits, however 0 is the same as 0). 💡 Tip: Start with the smallest possible three-digit number and make adjustments to make it divisible by 3.
- A14
- B15
- C16
- D18
Show answer & explanation
Correct answer: B
25% more than the number of rainy days in May means we need to find 25% of 12 and add it to 12. 25% of 12 is 0.25 x 12 = 3, so the number of rainy days in June is 12 + 3 = 15. 💡 Tip: Understand what '25% more' means and how to calculate it.
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Who can compete in MATHCOUNTS?
U.S. students in grades 6–8, through registered school teams — chapter, state, and national rounds run each spring.
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